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Energy of each photon

Another parameter present in the expected total count formula is the energy P of each photon.

The energy of each photon is:


 \begin{displaymath}P_{\lambda}=\frac{h\cdot c}{\lambda}=\frac{6.62620\cdot10^{-3...
...} ~m}=\frac{1.986\cdot10^{-19}}{\lambda(\mu m)}~J\cdot ph^{-1}
\end{displaymath} (2.7)



Pascal Ballester
1999-07-29